Area Example

Posted on October 22nd, 2008 by admin

Find the area of the shaded shape.   All measurements are in cm

Area of shaded portion

Area of shaded portion

Solution:

Area of the rectangle = 11 cm x 10 cm = 110 cm^2

Area of half the rectangle = {{110} \over 2}cm^2 =55cm^2

Area of unshaded triangle = {1 \over 2}b \times h={1 \over 2}10 \times 4cm^2 =20cm^2

Area of shaded portion =

Area of half the rectangle - Area of unshaded triangle = 55 - 20 = 35cm^2

Tags: Number, Year 7 // Add Comment »

Estimate 2.97 x 46

Posted on October 12th, 2008 by admin

2.97 x 46 \approx 3 x 50 = 150

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Round to the nearest 1000

Posted on October 6th, 2008 by admin

Round 14569 to the nearest 1000

Ans:

The thousandth unit is 4, the hundredth unit is 5 so 4 will be rounded up.   Therefore 14569 rounded to the nearest 1000 is 15000.

Tags: Form 1, Number, Year 7 // Add Comment »

Increase a decimal

Posted on September 29th, 2008 by admin

Increase 4.51 by (1/10)th

1/10 = 0.1

So 4.51 + 0.10 = 4.61

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Find a square root by factorising (Example 1)

Posted on September 29th, 2008 by admin

Use factorising to find this √324

324 = 2 x 162

162 = 2 x 81

81 = 9 x 9

So √324 = 2 x 2 x 9 x 9

Group into pairs: 324 = 2 x 9 x 2 x 9 = 18 x 18 = 182

So √324 = 18

 

Tags: Number, Year 8 // Add Comment »

Welcome

Posted on September 22nd, 2008 by admin

Welcome to Freemaths.co.uk. This site will offer free maths worked examples, free maths games and free maths quizzes. So, please come again.

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